# What does 3 sqrt 2

## How does partial root extraction work?

### Non-pullable roots

A root cannot be extracted if the exponent of the power below the root is not a multiple of the root exponent and is smaller than the root exponent.

$ \ sqrt [3] {16} = \ sqrt [3] {4 ^ 2} $

You can see that the value of the exponent is neither greater than the root exponent nor a multiple of the root exponent.

A root cannot be extracted if the exponent of the power below the root is not a multiple of the root exponent and is smaller than the root exponent.

$ \ sqrt [2] {a} $, $ \ sqrt [3] {a ^ 2} $

**Non-pullable roots**

$ \ sqrt {29} \ approx $ 5.38

$ \ sqrt {23} \ approx $ 4.79

$ \ sqrt {67} \ approx 8.18 $

### Partially pullable roots

**Partially pullable roots** are a special case that is crucial for us. They are characterized by the fact that the exponent of the power below the root is not a multiple of the root exponent, but is greater than the root exponent.

A root is partially extractable if the exponent of the power below the root is greater than the root exponent, but is not a multiple of the root exponent.

$ \ sqrt [2] {a ^ 5} $, $ \ sqrt [3] {a ^ 8} $

### Procedure for partial root extraction

When you partially pull the roots, you break them apart **partially pullable root into a pullable and a non-pullable part**. This means that you break the radicand under the root into a product of two numbers. You have to be able to pull the root of one of these numbers.

$ \ sqrt {44} = \ sqrt {4 \ cdot 11} $

**Factors under the root**

$ \ sqrt {a \ cdot b} = \ sqrt {a} \ cdot \ sqrt {b} $

$ \ sqrt {44} = \ sqrt {4 \ cdot 11} = \ sqrt {4} \ cdot \ sqrt {11} = 2 \ cdot \ sqrt {11} $

As you can see, we've transformed the partially extractable root into a product of an integer and a non-extractable root.

**Partial root extraction**

$ \ sqrt {45} = \ sqrt {9 \ cdot 5} = \ sqrt {9} \ cdot \ sqrt {5} = 3 \ cdot \ sqrt {5} $

$ \ sqrt {8} = \ sqrt {4 \ cdot 2} = \ sqrt {4} \ cdot \ sqrt {2} = 2 \ cdot \ sqrt {2} $

$ \ sqrt [5] {128} = \ sqrt [5] {2 ^ 5 \ cdot 2 ^ 2} = \ sqrt [5] {2 ^ 5} \ cdot \ sqrt [5] {2 ^ 2} = 2 \ cdot \ sqrt [5] {4} $

Test your newly learned knowledge now with our exercises! Good luck with it!

- Why am I not answering your question
- Is the world a video game
- How was life in the 60s
- When can a diabetes professional help you
- Soft cookies are stale cookies
- What do you think of ANR relationships
- Can vitamin C be taken at night
- Do Donald Trump's tariffs work
- Have you ever faced a dirt hole
- What fees does Steam charge developers
- What is the healthiest non-diet soda
- Why not balls made of iron
- Who was the first bad Roman emperor
- Is drinking soda once a day bad
- Can coconut water cure sore throats
- What is the data type
- How do Coursera and Udacity compare
- How do cryptocurrencies work
- What is rolling friction
- Why is US foreign policy so interventionist
- Does health insurance cover dental care?
- Will natural gas recover
- Hot chocolate can cause cancer
- Is money more important than knowing why?