# What is the relationship between grams liter

**Mass, amount of substance, atomic mass, molar mass**

**Dimensions**

When a diamond burns completely with the mass

*M.*= 1 gram (1g) in pure oxygen you can weigh the diamond, the required oxygen and also the reaction products. The physical base quantity mass is given in the unit kilogram or gram. From 1889 to 2019, the original kilogram stored in Paris was used as the reference weight. As of May 20, 2019, the base unit kilogram will be derived from Planck's constant.

Physical base size | Dimensions |

dimension | M. |

Formula symbol | m |

unit | kg, g |

**Amount of substance**

In chemistry, substances are viewed as dynamic systems. When burning a diamond, you not only want to know how much oxygen is being used, but also the ratio of the atoms involved. This requires the physical base quantity of the amount of substance with the unit mole:

Physical base size | Amount of substance |

dimension | N |

Formula symbol | n |

unit | mol |

The definition, valid from May 20, 2019, specifies an absolute number: *“One mole is 6.02214076 × 10 ^{23 }Particles (atoms, molecules, ions, etc.). "*This number is fixed, it is called

**Avogadro's constant**N

_{A.}.

The old definition, valid until May 19, 2019, derived the mole as a relative number depending on the carbon: The amount of substance 1 mole contains as many particles as there are atoms in 12 grams of isotopically pure C-12 carbon.

**Atomic mass**

The atomic masses of hydrogen or carbon atoms can now be determined relatively precisely through experimental arrangements. One twelfth of the mass of the carbon isotope C-12 is used as a reference value:

Reference value atomic mass | |

Formula symbol | m |

unit | g, u |

Reference value | 1u = 1.660539040 × 10^{−24} G 1u = one twelfth the mass of a C-12 atom |

**Proton mass**

*m*

*= 1,672621898 × 10*

_{p}^{−24}g = 1.007276466889 u

**Neutron mass**

*m*= 1,674927471 × 10

_{n}^{−24}g = 1.008664915880 u

**Electron mass**

*m*

_{e}**= 9,109383560 × 10**

^{−28}g = 0.000548579909 u

When specifying the values, it is neglected that the atoms are also dependent on their energy, but this should not be discussed further here. Be in chemistry

**relative atomic masses**used. The relative values all relate to the value 1u.

isotope | Relative atomic mass of the isotopes |

Carbon isotope C-12 | 12 u |

Gold isotope Au-197 | 196,966569 u |

196.966569 grams of gold contain as many atoms as 12 grams of the pure carbon isotope C-12. Many elements occurring in nature are mixed elements: they contain several different isotopes in their composition. While there is only one natural isotope in gold (Au-197), there are two natural isotopes in carbon, for example: C-12 and C-13. When specifying the relative atomic masses in the periodic table, the value refers to an average value of the atomic masses of the isotopes calculated according to the natural frequency. If only one isotope occurs in nature, then the relative atomic mass in the periodic table describes this isotope. If several natural isotopes occur in an element, then it is a mean value, calculated according to the frequency.

Element name in the PSE | Relative atomic mass of the elements |

Carbon (2 isotopes) | 12.01 u |

Hydrogen (2 isotopes) | 1.008 u |

Oxygen (3 isotopes) | 15,999 u |

Gold (1 isotope Au-197) | 196,966569 u |

**Molar mass, molar mass**

The molar mass can be derived from the basic quantities of mass and amount of substance

*M.*be derived. The unit is KiIograms per mole (kg / mol) or grams per mole (g / mol). The relationship applies:

*M.*=

*m ÷ n = N*

_{A.}*× m*

_{M.}*m*Dimensions

*n*Amount of substance

*N*

*Avogadro's constant*

_{A.}*m*

*Particle mass*

_{M.}For an element that is not in molecular form, the numerical value is practically the same as the value given in the periodic table for the relative atomic mass. A gold atom has a relative atomic mass of 196.97u. So the molar mass for gold is:

*M = 196.97 g / mol*

With chemical compounds like H

_{2}O and also for elements that are in molecular form such as hydrogen H

_{2}or oxygen O

_{2}, the value must be multiplied according to the number of atoms in the compound or the index numbers in the sum formula. The molar mass for water is:

*M = 2*

*X 1.01 g / mol + 1*

*X 16.00 g / mol = 18.02 g / mol*

**1st exercise example, molar salt**

**L.**

**Prepare a solution with a certain concentration**

__Task:__An aqueous sodium chloride solution is to be produced which contains 1 mol of sodium chloride in one liter of solution. The concentration of the solution should be 1 mole per liter.

__Method:__Sodium chloride has the molecular formula NaCl. First, the relative atomic masses of the atoms involved from the periodic table are used.

*M. _{NaCl} = M_{N / A} + M_{Cl} = 22.99 g / mol + 35.45 g / mol = 58.44 g / mol*

**2nd exercise example: Determine the amount of substance from a given portion of substance**

__tasks__

__s__

__position:__What is the amount of substance approximately one gram of natural carbon?

__Method:__The equation for deriving the molar mass is first transformed. Then you can use the values accordingly. So 1 gram of carbon is roughly one twelfth of a mole.

*M = m*

**÷***n*| Reshaping

*n = m*

**÷***M.*

*n = 1g*

**÷***12.01 mol / g ≈ 1/12 mol*

**3rd exercise example: diluting a concentrated solution**

__Task____:__ Prepare an aqueous solution with a concentration of 1 mol per liter from 37% hydrochloric acid. Enter a recipe for this!

__Method:__ First you have to calculate how many moles of hydrogen chloride HCl are dissolved in one liter of 37% hydrochloric acid. It should be noted that the density of 37% hydrochloric acid is 1.18 grams per cubic centimeter. The molar mass of hydrogen chloride is 36.46 grams per mole. Now you have to find out how many grams of hydrogen chloride are dissolved in one liter of 37% hydrochloric acid. The percentage is given in percent by mass: In one kilogram of 37% hydrochloric acid, 370 grams of hydrogen chloride would be dissolved. With the help of the equation for density you can first calculate how much 1 liter of 37% hydrochloric acid weighs:*D = m ÷V |* Reshaping

m = D

m = D

*× V*

*m = 1.18*g / cm³

*X 1000 cm³*

*= 1180 g*

So how much is 37% of 1180 grams? Multiplying the 1180 grams by 0.37 gives a value of 436.6 grams, which means that there are 436.6 grams of hydrogen chloride dissolved in one liter of 37% hydrochloric acid. Now you need the equation for the molar mass:

*M = m ÷n |* Reshaping

n = m

n = 436.6g

n = m

*M.***÷**n = 436.6g

*36.46 g / mol***÷***≈ 12 mol*

In one liter of 37%, fuming hydrochloric acid, about 12 moles of hydrogen chloride are dissolved. To prepare the solution 1 mole per liter, measure one twelfth of a liter in the fume cupboard (*≈*83 milliliters) of 37% hydrochloric acid in a measuring cylinder. This portion is dissolved in half a liter of distilled water in a volumetric flask and then made up to the 1 liter mark. Caution: "Never put water on the acid, otherwise the monster will happen!" Since it was rounded, the approach is not exactly exact, so that you only get an approximate solution with a concentration of 1 mol per liter. In this approach, a more precise calculation is made:

*M = m ÷ n |* Reshaping

m = M

m = M

*× n*

m = 36.46 g / mol

m = 36.46 g / mol

*× 1 mol / l = 36.46 g*

Inserting the values in the rule of three:

*1000 ml ÷ 436.6 g = x ml ÷ 36.46 g | *Reshaping

x =

x =

*1000 ml x 36.46 g*

*436.6 g***÷***≈ 83.5 ml*

**4. ****Ü****exercise example**

The concentration of the dissolved sodium hydroxide of a sodium hydroxide solution (sample solution) is not known. The concentration should be determined with a neutralization by titration. During the titration, exactly 7 milliliters (7 ml) of a 1 molar standard solution of hydrochloric acid are used until the neutralization point is displayed in 20 milliliters (20 ml) sample solution. What is the concentration of the caustic soda, neglecting the density?

Solution control

**Create book individually: basic text mass, amount of substance, atomic mass, molar mass**

>

**Table of Contents**

- The market for nutritional supplements has reached its peak
- Politics is good for students
- What is the best beach in myanmar
- Can an alcoholic drink moderately
- What are complementary colors for brown
- What is an attractive euphemism for gamification
- Expertise is required to come up with an idea
- Why is there tapioca in bubble tea

- Where can I effectively post my links
- Is Post Malone gay
- Have you been busy lately?
- Can or will reunite Malaysia and Singapore
- What role does production technology play
- What meal changed your life
- Do you need a house cleaning service
- How do I download Steam
- What kind of business can not be successful online
- Kiwis greet the Singaporeans
- What are some surprising statistics about meditation
- Safe Shop is reliable for investments
- What is your aha moment in your work
- What is Jordan Peterson so afraid of?
- Is Lonar Sarovar in Maharashtra worth a visit
- What is a Birmingham painting
- Where can I buy foreign commemorative coins?
- How can you make 3000 quickly
- Is God almighty, omniscient and almighty
- What are China's dishes
- How does malaria kill
- Why do schools separate gifted students
- What is a roll cap
- Money buys time